Question

the density of 3 molal solution of naoh is 1.110 g ml^(-1 calculate the molarity of the solution)

Answer 1

Explanation:

Molality of NaOH solution =3 m

Molality=number of moles of solute/mass of solvent(kg)

3=massofsolventn

mass of solvent =31000n g

Also, number of moles=mass/molar mass

For NaOH solution, n=40m

Density of solution,ρ=1.110g/mL

Mass of 1 mL solution =1.11g=msolute+msolvent

3n×40+1000n=1.11

n=2.97×10−3 mol

Molarity = number of moles of solute/ volume of solution(L)

M=0.0012.97×10−3=2.97M