Question

The density of 3M solution of NaCl is 1.2 g/ml. Calculate the molality of the solution​

Answer 1

Answer:

Find your answer in the pic

Explanation:

Hope this helps you

Answer 2

Answer:

2.7915 Molal

Explanation:

3 M solution means there are 3 moles of NaCl salt in 1 liter. Molecular weight of NaCl is 58.44.

Hence, there are 3 x 58.44. gms in 1 liter of water.

Density = mass/volume

Mass of 1 liter of solution 1.25 gms/ml*

1000 ml = 1,250 gms

V = volume of water added to make the solution.

175.32 + 1 gm/ml* V = 1,250 gm

=> V = 1,074.68 ml

So, 1,074.68 ml or 1,074.68 gms of water is mixed with 3 moles of NaCl to make 3M solution.

Molality = mass of solute in number of moles/mass of solvent in kg

=> 3/1.07468 kg

=> 2.7915 Molal