Question

The density of 3m solution of nacl is 1.25 g/ml calculate the molality of the solution

Answer 1

Explanation:

$density =1.25 \: g/mol$

$solution =3 \: m$

$NaCl \: का \: मोलर \: द्रव्यमान-$

$M(1) =23+35.5 =58.5 \: g/mol$

$molality=\frac{1000*m*d}{1000-mM1}$

$=>\frac{1000*3*1.25}{1000-3*58.5}$

$=>\frac{3750}{1000-175.5}$

$=>\frac{3750}{824.5}$

$=>4.55 मोलल$