Question

The density of 3M solution of NaCl is 1.25g/ml.Calculate molarity.?

Answer 1

hopefully it helps you

Answer 2

☆As we know that :-

$= > m = \frac{M \times 1000}{d \times 1000 \: \ - \: M \times M'}$

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HERE

» M = Molarity

» m = molality

» d = density

» M' = molar mass of solution.

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$= > m = \frac{3 \times 1000}{1.25 \times 1000 - 3 \times 58.44} \\ \\ = > m = \frac{3000}{1225 - 175.32} \\ \\ = > m = 2.79 \: m$
_______________[ANSWER)]

☆HENCE THE MOLALITY OF SOLUTION IS "2.79 m"

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