Chemistry, asked by jcbasavaraju, 6 months ago

The density of 3m solution of NACL is 1.25gml calculate the molality of the solution

Answers

Answered by aithimouleendra

3

Answer:

Explanation:

given 3mol/lit

wt of nacl in lit =3*58.5=175.5g

molality= moles of solute /mass of solvent in kg

density =1.25g/ml=1250gm/ltr=1.25kg/l

1250-175.5=1075.5

molalty=3/1075.5=2.79

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