the density of 3molal solution of NaOH is 1.110 g/mL.Calculate the molarity of the solution
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A 3 molal solution is prepared by dissolving 3 moles (40 x 3 = 120g) of NaOH in 1000g 0f water.
Total mass of such solution containing 3 moles of the solute = 1000 +120 = 1120g
Density of this solution = 1.11og/ml
Density = mass/volume
Total volume of this solution = 1120/1.110 = 1009mL = 1.009L
Thus, 3 moles of NaOH are present in 1.009L of the solution.
So, no of moles present in 1L of the solution = 3 x 1/1.009 = 2.973 (answer)
Total mass of such solution containing 3 moles of the solute = 1000 +120 = 1120g
Density of this solution = 1.11og/ml
Density = mass/volume
Total volume of this solution = 1120/1.110 = 1009mL = 1.009L
Thus, 3 moles of NaOH are present in 1.009L of the solution.
So, no of moles present in 1L of the solution = 3 x 1/1.009 = 2.973 (answer)
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