the density of 96% (w/w)h2so4 solution is 1.84g/ml . what is the molarity of solution and what volumeof solution is required for preparation of 500 ml of 1M h2so4 solution
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Molarity of solution is calculated as below:-
let total weight of solution be 100 gm
then the volume of 100gm solution= mass/density
=100/1.84=54.3478
molarity=(weight of H2SO4 in solution*1000)/(Molecular weight of H2SO4*Volume of solution)
=(96*1000)/(98*54.3478)
=18.0245 Molar
Using Formula M1V1=M2V2, we get volume which is as follows:-
(18.0245*V1)=(500*1)
V1=500/18.0245=27.74 ml
hope this helps!
let total weight of solution be 100 gm
then the volume of 100gm solution= mass/density
=100/1.84=54.3478
molarity=(weight of H2SO4 in solution*1000)/(Molecular weight of H2SO4*Volume of solution)
=(96*1000)/(98*54.3478)
=18.0245 Molar
Using Formula M1V1=M2V2, we get volume which is as follows:-
(18.0245*V1)=(500*1)
V1=500/18.0245=27.74 ml
hope this helps!
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