Question

The density of a 3.6M sulphuric acid solution that is 29% h2so4 molar mass98 by mass will be

Answer 1

molarity of sulphuric acid = 3.6 M

percentage by mass of H2SO4 in solution = 29%

molar mass of H2SO4 = 98 g/mol

using the formula,

Molarity = percentage by mass × 10 × density/molar mass of solute

or, 3.6 = 29 × 10 × density of solution/98

or, 3.6 × 98/290 = density of solution

hence, density of solution = 1.216 g/mL

Answer 2

Mass % of H2SO4=29%

(i.e)

100g solution contains 29g H2SO4

Let the density of solution (in g/ml) is d

Molarity of solution=Moles of

H2SO4Volume of solution(ml)×1000

(M=3.60)

2998100d×1000=3.60

d=1.22g/ml