Chemistry, asked by shilpabiswas114, 10 months ago

the density of a 56% by weight of aqueous solution of 1-propanal (ch3-ch2-ch2-oh) is 0.8975 g/cc.what is the mole fraction of 1-propanal

Answers

Answered by nagathegenius

3

Answer:

Explanation:

Calculate molality

By finding molarity

Molarity = 1000rho/1000m + mwsolute

8.38 = 897.5 / 1000m + 60

8380m + 502.8 = 897.5

8380m =394.7

m= 0.047

Moles = 0.047

Moles of solvent = 55.55

Mole fraction =0.0008

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