The density of a gas at 27'c and 1 atm is d. pressure remaining constant, at which of the following temperature will its density become 0.75 d?
a) 20'c
b) 30'c
c) 400'c
d) 300 k
Answers
Answered by
92
As we know that, PV = nRT
or PV = (m/M) RT
or PM = (m/V) RT = d RT
In condition (1): PV = d R 300
In condition (2): PV = 0.75d RT
Dividing condition (1) by (2), we get:
1 = (300)/0.75T
or T = 400 K
Hence, option (c) i.e. 400 K is the right answer.
Anonymous:
hi mehak
Answered by
24
Answer:
this is the answer to the question
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