Question

the density of a gas is found to be 1.56 g dm-3 and 0.98 bar pressure and 65 degree celcius calculate the melar mass of the gas​

Answer 1

Given:-

→ Density of the gas = 1.56 g dm⁻³

→ Pressure = 0.98 bar

→ Temperature = 65°C

To find:-

→ Molar mass of the gas.

Solution:-

Firstly, let's convert the units of density and temperature.

Density :-

⇒ 1 g dm⁻³ = 1 g L⁻¹

⇒ 1.56 g dm⁻³ = 1.56×1

⇒ 1.56 g L⁻¹

Temperature:-

⇒ 0°C = 273 K

⇒ 65°C = 273 + 65

⇒ 338 K

________________________________

Value of 'R' [Gas Constant], when pressure is in bar :-

0.0831 L bar K⁻¹ mol⁻¹

________________________________

Now, we know that :-

P = dRT/M

Where :-

• P is the pressure.

• d is density of the gas.

• R is Gas Constant.

• T is temeprature.

• M is molar mass of the gas.

Substituting values, we get :-

⇒ 0.98 = 1.56 × 0.0831 × 338/M

⇒ 0.98M = 43.82

⇒ M = 43.82/0.98

⇒ M = 44.71 g/mol

Thus, molar mass of the gas is 44.71 g/mol .

Answer 2

Explanation:

Given:-

→ Density of the gas = 1.56 g dm⁻³

→ Pressure = 0.98 bar

→ Temperature = 65°C

To find:-

→ Molar mass of the gas.

Solution:-

Firstly, let's convert the units of density and temperature.

Density :-

⇒ 1 g dm⁻³ = 1 g L⁻¹

⇒ 1.56 g dm⁻³ = 1.56×1

⇒ 1.56 g L⁻¹

Temperature:-

⇒ 0°C = 273 K

⇒ 65°C = 273 + 65

⇒ 338 K

________________________________

Value of 'R' [Gas Constant], when pressure is in bar :-

0.0831 L bar K⁻¹ mol⁻¹

________________________________

Now, we know that :-

P = dRT/M

Where :-

• P is the pressure.

• d is density of the gas.

• R is Gas Constant.

• T is temeprature.

• M is molar mass of the gas.

Substituting values, we get :-

⇒ 0.98 = 1.56 × 0.0831 × 338/M

⇒ 0.98M = 43.82

⇒ M = 43.82/0.98

⇒ M = 44.71 g/mol

Thus, molar mass of the gas is 44.71 g/mol .

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