Question

The density of a gaseous mixture containing He and O2 at 27 degree Celsius and 760 torr is 0.50 g/l . The amount fraction of he in the mixture is?

Answer 1

Answer:

First, you can use the ideal gas law to calculate the average molar mass of the gas mixture:

PV=nRT

n=mass/molar mass

PV=(mass/molar mass)RT

density=mass/V

Rearranging the equation we get

molar mass=(density)RT/P

Molar mass=(0.50g/L)(0.0821 Latm/molk)(300k)/0.9487atm

molar mass=12.98g/mol

Now let x=mole fraction of He and

         1-x=mole fraction of O2

12.98g/mol=4(x)+32(1-x)

12.98=4x+32-32x

-19.02=-28x

x=0.67*100%

67%

Answer 2

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