Chemistry, asked by sciencefreek, 4 days ago

The density of a H2SO4 solution is 2.98 g/mL. The molality of one litre solution of 98% of H2SO4 (weight/volume) is :

Answers

Answered by ananyasnigdha
0

Answer:

12.1

Explanation:

Density of acid soln = 1.8 g/ mL.

1000 mL volume will weight 1800g.

Mass of H2SO4

​ present =1800×  100/ 90

​  =1620g

Number of mole of H2SO4

​=  molar mass/ actual mass

​  =  98/ 1620

​ =16.53 mol

Thus molarity of stock solution is 16.53 M.

To prepare 1000 mL of 0.2 M solution,  

M  1 V 1  = M2 V2

​ 16.53× x =0.2 × 1000

x=  16.53/ 200

​ x=12.099 ml

x=12.1 ml

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