The density of a material in CGS system of units is 4g/cm^3. In a system of units in which unit of length is 10 cm and unit of mass is 100 g, the value of density of material will be..... It is a physics problem Pls give the answer its urgent
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Density in CGS system is = 4 gms/ cm³
Unit of length = 1 cm unit of mass = 1 gm
Another system of units:
unit of mass = gm' = 100 gm unit of length = cm' = 10 cm
=> 1 gm =
and 1 cm = 
Substitute these values in the value of the density. Now density of the material:

Thus in the new system the value of density will be 40 units.
Unit of length = 1 cm unit of mass = 1 gm
Another system of units:
unit of mass = gm' = 100 gm unit of length = cm' = 10 cm
=> 1 gm =
Substitute these values in the value of the density. Now density of the material:
Thus in the new system the value of density will be 40 units.
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Explanation:
40 is the answer .......
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