Physics, asked by Ashvaneet4727, 10 hours ago

The density of a metal at normal pressure is rho.Its density when it is subjected to an excess pressure P is rho'.If the bulk modulus of the metal is B,the ratio rho' to rho is_

Answers

Answered by aritramal00
0

Answer:

1−p/B

1

B=−V

dV

dP

Thus, ΔV=−

B

pV

or V

−V=−

B

pV

Or, V

=V(1−

B

p

)

Now, ρ

=

V

m

=

V(1−

B

p

)

m

=

(1−

B

p

)

ρ

Explanation:

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Answered by s04328fannielois
0

Answer:

B  =  − V d P d V

Thus,  

Δ V  =  − p V B  or  V ′  −  V  =  − p V B

Or,

V ′  =  V  ( 1  − p B )

Now,  

ρ ′  = m V ′  = mV  ( 1 − p B )  =  ρ  ( 1 -p B )

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