Question

the density of a metal which crystallises in BCC lattice with unit cell edge length 300pm & molar mass 50g mol-¹ will be.​

Answer 1

Answer

Density of a Metal = 13.5*10^-4m³mol-¹

Explanation:

volume of cube cell,

a³ = (300)³ = 27000000*10^-12

= 2.7*10^-5

Density p = molar mass * volume

= 50*2.7*10^-5

= 13.5*10^-4m³mol-¹

Answer 2

The mass of a solid divided by the volume occupied by the particle is known as crystal density.

Given:

• Type of crystal lattice = BCC.
• Unit cell edge length = 300pm
• Molar mass = 50g/mol

To find:

• Density of the metal crystal in BCC.

Formula used:

• Theoretical density of crystal = ρ = $\frac{nM}{N_{0}a^{3}}$ $g/cm^{3}$
• Given for bcc n = 2, a=300 x 10^-10, M = 50g
• ρ = $\frac{2*50}{6.022 * 10^{23} (300^{3}) *(10^{-10})^{3} }$
• =6.15 $g/cm^{3}$

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