Question

The density of a non-uniform rod of length 1 m is given by ρ (x) = a(1+bx2) where a and b are constants and o ≤ x ≤1. The centre of mass of the rod will be at
(a) 3 (2 + b) / 4 (3 + b)
(b) 4 (2 + b) / 3 (3 + b)
(c) 3 (3 + b) / 4 (2 + b)
(d) 4 (3 + b) / 3 (2 + b)

Answer 1

Answer:

C. 3(3+b) /4 (2+b)