Question

The density of a non-uniform rod of length 1 m is given by
⍴(x) = a (1 + bx²) where, a and b are constants and
0 < x < 1.The centre of mass of the rod will be at
(a)3(2 + b)/4(3 + b)
(b)4(2 + b)/3(3 + b)
(c)3(3 + b)/4(2 + b)
(d)4(3 + b)/3(2 + b)

Answer 1

Answer:

The density of a non-uniform rod of length 1m is given by ρ(x)=a(1+bx2) where a and b are constants and 0 ≤x≤1. The centre of mass of the rod will be at: A