Question

the density of a solid ball is determined in an experiment the diameter of ball is measured with a screw gauge whose pitch is 0.5 mm and there are 50 divisions on the circular scale. the reading on the main scale is 2.5 mm and that on the circular scale is 20 divisions if the measured mass of the ball has a relative error of 2% the relative percentage error in density is

Answer 1

Heya mate.....

3.1%

@skb

Answer 2

Given

Screw gauge readings

Pitch =0.5mm

Circular scale division=50

Main scale reading =2.5 mm

Circular scale division reading =20 divisions

Relative error =2%

So

Then dimensions reading from screw gauge= Dia of ball

S.G. Reading = main scale reading +[(pitch/circular scale division) x circular scale division reading]

=2.5+[(0.5/50)x20)]

=2.5=0.2

=2.7mm

Density = mass/ volume

Volume =4/3 pi r³

=10.3065mm³


Density (§ using this symbol for rho)

Mass=m

Volume =v

§= m/v

$rho = \frac{m}{ \frac{4}{3}\pi (\frac{d}{2})^{3} }$

% error in density = dm/m x100 + (dD/D) 3 x 100

=3.1%

This is ur ans hope it will help you