Question

The density of a solution containing 13% by mass of sulphuric acid is 1.09 gm/ml . Calculate

the molarity and normality of solution. ​

Answer 1

..........................

Answer 2

Answer:

Volume of 100 g of the solution

= 100/d= 100/ 1.09ml

=100/1.09×1000 litre

= 1/1.09×10

Number of moles of H²SO⁴ in 100 g of the solution =13/98

Molarity =No. of moles of H²SO⁴/volume of sol in litre

=13/98 × 1.09×10/1

=1.445M

We know that,

Normality = Molarity ×n

=1.445×2 [n=mol mass/ equ mass=98/49=2]

=2.89N

Hence, the molarity of the given solution is 1.445 M and normality is 2.89 N