Question

The density of a solution containing 14% by mass of sulphuric acid is 1.05g/ml. what is molarity of solution

Answer 1

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Answer 2

Answer: The molarity of solution is 1.5 M

Explanation:

We are given: 14% by mass of sulfuric acid.

This means that 14 grams of sulfuric acid is present in 100 grams of solution.

• To calculate the volume of solution, we use the equation:

$\text{Density}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of solution = 1.05 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$1.05g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=95.23mL$

• To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (sulfuric acid) = 14 g

Molar mass of sulfuric acid = 98 g/mol

Volume of solution = 95.23 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{14g\times 1000}{98g/mol\times 95.23mL}\\\\\text{Molarity of solution}=1.5M$

Hence, the molarity of solution is 1.5 M