Question

The density of air is 0.0012 gm/cc, 19.30 gm/cc is the density of gold,if we measured 1kg gold in a balance what will be the authentic weight of gold?

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Answer 1

Answer:

Given,

Density of air = 0.0012 gm/cc = 1.2kg/m^3

Density of gold = 19.30 gm/cc = 19300 kg/m^3

Let,

Real mass of gold = m and volume of gold = V

Therefore, V = m/p(sub g) (p is row or density and g is for gold)

If equivalent mass of air is m(sub a) then

V = m (sub a) / p(row) (sub a)

Or, m(sub a) = Vp(row) (sub a)

Therefore Equivalent weight of air, W = mg =Vpg

Again Equivalent weight of gold, W = mg

Mass of gold is measured by the balance = 1kg

According to the question,

W(sub g) - W(sub a) = 1kg * g

Or, mg - Vp(sub a) *g = 1kg * g

Or, m - Vp(sub a) = 1 * g

Or, mg - (m/p(sub g)) p(sub a) * g = 1

Or, m{ 1 - p(a)/p(g)} = 1

Or, m {1 - (1.2 * 19300)} = 1kg

Or, 0.99937 = 1kg

Or, m = 1.00063

So real mass of 1kg gold is 1.00063

Explanation:

Its a huge and complicated solution but i think it'll help you for sure...