The density of air is 0.001293 gm per cc its vapour density will be at stp
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Answered by
7
The density of air is 0.001293 g/cc at STP. Its vapour density is
Answer:
14.49
Explanation:
At STP, 22.4 litres of gas is equal to 1 mole.
Given density=0.001293 g/cm³
1 mole has 0.001293 gram
22.4 ml has 0.001293 x 22.4/10⁻³
Molecular mass=28.97
Vapour density= Molecular mass/2 = 14.485
Answer:
14.49
Explanation:
At STP, 22.4 litres of gas is equal to 1 mole.
Given density=0.001293 g/cm³
1 mole has 0.001293 gram
22.4 ml has 0.001293 x 22.4/10⁻³
Molecular mass=28.97
Vapour density= Molecular mass/2 = 14.485
Answered by
2
Answer:14.48gm
Explanation:Since molecular weight = weight of 22400 cc at STP
Hence vapour density = Weight of 11200 cc
So, vapour density = 0.001293 × 11200 = 14.48
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