Chemistry, asked by supraja2003, 9 months ago

The density of air is 0.001293gm.
per c.cets vapour density will
be at STP.
1)10 2)16 3)1.43 4)14.3​

Answers

Answered by Itzraisingstar
4

Answer:

Explanation:

As,you know vapour density is molecular weight/2,

1 mole gas is 22.4 litre at STP,

or 22400 ml at STP,

So,mole =given mass/molecular mass,

density =mass by volume,

So,mass is density*volume,

density*volume/molecular mass,

So mole = density*volume/2*vaapour density,

1 =0.001293*22400/2*vapour density,

1=28.96/2*vapour density,

So,vapour density is 29.12/2,

14.56,

So,14.56 is the vapour density of air.

Hope it helps you

Similar questions