The density of air is 1.28 g litre^-1 . Express it in : (a) g cm^-3 (b) kg m^-3 .
Answers
Answer:
sorry I didn't understand anything
Answer:
a) 0.00128 g/cm³ or 0.00128 g cm⁻³
b) 1.28 kg/m³ or 1.28 kg m⁻³
Step-by-step explanation:
Given:
The density of air is 1.28 g litre⁻¹.
To express it in:
a.) g cm⁻³
b.) kg m⁻3
Solution:
a.)
First expressing it in g/cm³ or g cm⁻³.
1 g/litre = 1/1000 g/cm³
1.28 g/litre = 1.28 × 1/1000 g/cm³
= (1.28/1000) g/cm³
Put decimal point after 3 numbers rest will remain same. ( For adding 3 more numbers we will take zero ( 0 ) in place of that numbers as;
= 0.00128 g/cm³
[ Also before the point we will take 0 and not just leave the blank character as .00128 g/cm³. Before the decimal point we don't have any number, so we will take zero.]
b.)
First expressing it in kg/cm³ or kg cm⁻³.
1 g/cm³ = 1/1000 kg/cm³
(1.28/1000) g/cm³
= (1.28/1000) × 1/1000 kg/cm³
Here, 1000 in both numerator and denominator gets cancel, we have:
= 1.28 kg/cm³
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