Question

the density of alcohol is 600 kgm3 express it in g cm3​

Answer 1

Good afternoon :)

$\rho = 6 \times {10}^{ - 1} \frac{g}{ {cm}^{3} }$

Explanation:

$\rho = \frac{mass}{volume}$

$\rightrightarrows\rho = \frac{600kg}{ {m}^{3} }$

1Kg=1000g

${m}^{3} = {1000000cm}^{3}$

Replacing the values

$\rho = 6 \times {10}^{ - 1} \frac{g}{ {cm}^{3} }$

Hope it help you

Answer 2

Answer:

• 0,6 g/m³

Step-by-step explanation:

600 kg/m³ → g/cm³

600 kg/m³ ÷ 1000 = 0,6 g/cm³