The density of an aqueous solution of nitric acid is 1.430 g/mL. If this solution contained 36.00% nitric acid by mass, how many mL of the solution would be needed to supply 150.20 grams of nitric acid.
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Explanation:
molarity = 8.17
volume = x lt
moles = 2.3841
volume = 0.29177 lt
volume = 291.77 ml
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