Question

The density of an ideal gas is 1.60 kg m-at 27° C and 1.0 10N/mº pressure and its specific
heat capacity at constant volume is 312 J kg K-1. Find the ratio of the specific heat capacity at
constant pressure to that at constant volume.​

Answer 1

Answer:

The specific heat at constant volume for a gas is given as (∂U∂T)V=cv ( ∂ U ∂ T ) V = c v . The specific heat at constant pressure for an ideal gas is given as (∂H∂T)V=cp=cv+R ( ∂ H ∂ T ) V = c p = c v + R .

Answer 2

Answer-1.67

Explanation:Given

Density of ideal gas:1.6kg/m^3

Temperature: 300k

Heat capacity at constant volume Cv: 312jkg^-1k^-1

Pressure: 1.01×10^5nm^-2

now,

pv=mrt =p/dt

r=p/dt = 210.41 jkg^-1k^-1

Also,

Cp-Cv=r

Cp=Cv+r

Cp=312+210.41=522.41

then,

Cp/Cv= 522.41/312

=1.67 ans