the density of crystalline NaCl is 2.165 g cm-³. Calculate the edge length of the cubic unit cell, if NaCl has face centred cubic lattice structure.
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Solution:
We know that ,
ρ=Na3(MNA)ρ=Na3(MNA)ρ=Na3(MNA)
Where
ρ=density=2.165gcm−3ρ=density=2.165gcm−3ρ=density=2.165gcm−3
M = molar mass = 58.5
NA=Avogadro′snumber=6.023×1023NA=Avogadro′snumber=6.023×1023NA=Avogadro number=6.023×1023
N = number of formula unit per unit cell = 4 (for fcc)
a3=NρMNAa3=Nρ(MNA)a3=Nρ(MNA)
=1.794×10−22=1.794×10−22=1.794×10−22
=5.64×10−8cm
Molar Volume =MolarmassDensity
58.82.165
3 cm
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