The density of cubic manganese is 7440 kg m-3. the lattice parameter a = 8.92 ĂĄ. find the number of atoms in the unit cell.
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Density(d) = no. of particle(z)×molarmass(M)/avogadro no.(Na) × edge length(a³)
d = z×M/ Na × a³
=> z = d×Na×a³/M
z = 7440×6.02×10²³×8.92³/54
z = 5.87× 10^14 atoms
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