Chemistry, asked by sidh9780, 10 months ago

The density of gas A is twice that of gas B, molecular mass of A is Half of molecular mass B, the partial pressure ratio of A and B is

Answers

Answered by dipendrakumarsharmap
32

I think ur doubt will be clear.

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Answered by Tringa0
9

Answer:

The partial pressure ratio of A and B is 4:1.

Explanation:

Density of gas A = 2d

Density of gas B = d

Molar mass of gas A ,m= \frac{1}{2}M

Molar mass of gas B ,m'= M

Density=\frac{P\times M}{R\times T}

Partial pressure of gas A = p_A

2d=\frac{p_A\times m}{R\times T}..(1)

Partial pressure of gas B = p_B

d=\frac{p_B\times m'}{RT}..(2)

Dividing (1) and (2):

\frac{2d}{d}=\frac{\frac{p_A\times m}{R\times T}}{\frac{p_B\times m'}{RT}}

2=\frac{p_A\times \frac{1}{2}M}{p_B\times M}

\frac{p_A}{p_B}=\frac{4}{1}

The partial pressure ratio of A and B is 4:1.

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