Question

the density of gas at 27 degree Celsius and 1 atmospheric pressure is 0.027 gram/ml. evaluate its molar mass

Answer 1

Answer:

PM/RT=Density

5×28/0.0821×295.7 T=22.7+273=295.7

=140/24.27697

=0.57667

the density of n2 gas is 0.57667

Answer 2

0.66501 Kg

Explanation:

It is given that we have a gas at 27 degree celsius and 1 atmospheric pressure .

We are supposed to calculate the molar mass of the gas.

We know that the gas law states that ,PV is contant at constant temperature.

$PV=nRT$

So we see the term density so we involve that term by dividing the mass with the volume part of LHS.

$PM=pRT$

where M is the molar mass of the gas and p is the density of the gas.

$Density=\frac{PM}{RT} \\\\T=27+273=300\\\\M=300*0.0821*0.027*\frac{1}{1} \\\M=0.66501 Kg$

Hence the molar mass is 0.66501 Kg