Question

The density of gold is 19.3 gm/cc. express its value in si unit?

Answer 1

19.3 g/cc=19300 kg/m3

Conversion base : 1 g/cm3 = 1000 kg/m3

Conversion base : 1 kg/m3 = 0.001 g/cm3

Answer 2

Answer:

The density of the gold in SI unit is $19300\ kg/m^3$

Explanation:

The density of gold is, $d=19.3\ g/cm^3$

We need to find the density in SI unit.

We know that, the conversions are as follows :

$1\ kg=1000\ g$

$1\ m=100\ cm$

$d=19.3\dfrac{g}{cm^3}=19.3\times \dfrac{1/1000\ kg}{(1/100\ cm)^3}$

$d=19300\ kg/m^3$

So, the density of the gold in SI unit is $19300\ kg/m^3$. Hence, this is the required solution.