Question

the density of gold is 19.32 g/cm³.calclate its density in si unit​

Answer 1

Answer:

Density in S.I units=19.32g/cm^3=(19.32×1000)kg/m^3=19320 kg/m^3

Answer 2

Given,

• Density of gold = 19.32 g/cm³

We know,

• SI unit of Density = kg/m³

In order to get the value of g/cm ³ in kg/m³ , we have to multiply the given value by 1000.

So,

SI unit density of gold = 19.32 × 1000

⇒ SI unit dnesity of gold = 19320 kg/m³

$\boxed{\displaystyle\sf{\therefore \:SI \:unit \:density \:of \:gold = 19320 \:kg/m^3}}$