the density of ice is 0.9 g/cm3. When it floats in water, what fraction of its volume will remain above surface?
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dencity of ice 0.9g/cm3
hence mass of 1cm3 of ice = 0.9g
density of water = 1g/ cm3
hence mass of 1cm3 of water is 1g
hence area under water will be 0.1 cm3
hence mass of 1cm3 of ice = 0.9g
density of water = 1g/ cm3
hence mass of 1cm3 of water is 1g
hence area under water will be 0.1 cm3
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Answer:
density of ice =0.9g/cm^3
density of water =1g/cm^3
By law of floatation the fraction of volume of ice above the water surface= density of water/density of ice
=1/0.9
= 1/10 part of ice is above the surface of water
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