Question

the density of ice is 0.92 g cm3 and the density of seawater is 1.035 g/cm3 find the total volume of an iceberg which floats with its volume 800 cm3 above water
Please Answer this question, this is urgent.​

Answer 1

Answer:

V = 7812.5

Explanation:

Given :

Density of ice =0.92 g cm

−3

Density of sea water =1.025 g cm

−3

Volumn of the ice berg above water =800cm

3

Let

′

v

′

be the volume of iceberg immereder in water

As per the law of floatation,

V

ν

=

Density of sea water

Density of ice

⇒

V

ν

=

1.025

0.92

=0.8976

⇒v=0.8976V

Volume of the iceberg over the surface of sea water is given by:

V(1−0.8976)=800

⇒V=800/(1−0.8976)

⇒V=7812.5 cm