The density of ice is 0.92g cm-3 and that of sea water is 1.025 g cm-3.Find the total volume of the iceberg which floats with its volume 800 cm-3 above water.
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Answer:
Explanation:
According to the principle of floating, an object that floats in a liquid displaces an amount of liquid equal to the mass of the object.
Therefore, if V is the volume of ice, its mass is V*density of ice = V*0.92gm.
Therefore, the amount of water displaced by the water = V*92gm
The volume of water displaced = V*0.92/density of water= V*(0.92)/1.025=0.897560975V.
Therefore 0.8997560975 of the volume of ice is sunk and (1-0.897560975) of its volume is above water. Or 0.102439024 of its volume is above see water.
If 800 cm^3 of ice is above water, then its volume x is given by:
0.102439024:800 cm^3 :: 1: x. So,
x=800/ 0.102439024=7809.52381 cm^3.
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