Question

the density of ice is 917kg/m^3 . what fraction of the volume of a piece of ice will be above water when floating in fresh water?

Answer 1

Since the force required to float the ice should be equal to the weight of ice
so,
buoyant force = weight of the ice = weight of water displaced

so,
weight of the ice = weight of the water displaced

let v1 = volume of the ice
d1 = density of the ice
v2 = volume of water displaced
d2 = density of the water

so,
v1 * d1 = v2 * d2

v1/v2 = d2/d1

v1/v2 = 1000/917. (since density of water is 1000kg/m^3

so here we can observe v1 is the total volume of ice and v2 is the volume of ice submerge in the water
so by reciprocal both the sides

v2/v1 = 917/1000

v2/v1 = 0.917

in percentage

v2/v1 * 100 = 0.917 * 100
v2/v1% = 91.7%
so the 91.7% part of ice is submerge in the water

so to calculate the part that is floating

100 - 91.7
= 8.3%

so 8.3% part of ice is floating on the water.
♡♥♡♥♡♥