Question

The density of ice is 920 kg per cubic metre and that of sea water is 1030 kg per cubic metre. What is The percentage of volume of an iceberg below sea water ?

Answer 1

The displaced water should provide the buoyancy force that equals the weight of the iceberg:

iceberg volume × 920 kg m-3 × g = displaced volume × 1030 kg m-3 × g  

∴ % of Displaced volume / iceberg volume = 920 / 1030 × 100

                                                                       = 0.89  × 100

                                                                       = 89%

→ 89% of the volume is under water and 11% of the volume is above the water.

IF HELPFUL PLS DO MARK AS BRAINLIEST

-IRKI♥-