Math, asked by vinayakajagnarine, 11 months ago

the density of lead is 11.35 g/cm3. determine the mass of the rectangular block of lead.
continue from the last question

Answers

Answered by Ritiksuglan
3

hey mates your answer is here

Solution :

For a fcc unit cell ,

Density =4×molarmassNA×a3

=4×207gmol−16.02×1023mol−1×a3

=11.35gcm−3

Then

a=(4×2076.02×1023×11.35cm−3)1/3

=4.95×10−8cm

a2–√=4r

From geametry

r=4.95×10−8cm22–√

=1.75×10−8cm

So the radius of lead atom is 1.75×10−8cm or 175pm

may be it's helpful for you

please mark me as brainliest ✌️✌️


Ritiksuglan: please mark me as brainliest ✌️✌️
Similar questions