Question

the density of lithium is...........glcc?
(fill in blank)
​

Answer 1

Answer:

a=3.5

A

˚

, ρ=0.53g/cm

3

, M

A

=6.94, Z=?

ρ=

N

A

×a

3

Z×M

A

0.53=

6.023×10

23

×42.875×10

−24

Z×6.94

Z=2

Therefore, 2 atoms of lithium are present in an unit cell.

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