Question

the density of material A is 1500 kg/m^3 and that of another material B is 2000 kg/m^3.it is found that the heat capacity of 8 volumes of A is equal to heat capacity of 12 volumes of B.the ratio of specific heats of A and B will be?

Answer 1

Given data:

The density of material A= 1500 kg/m^3

Density of material B = 2000 kg/m^3.

According to the findings,

Heat capacity of 8 volumes of A = heat capacity of 12 volumes of B

Ratio of specific heat= SA/ SB=?

The ratio of specific heat can be calculated by following formula:

Sa/ma x mb/Sb

Explanation is given in the following image.