Question

The density of Methane at 27 C and 2 atm is?​

Answer 1

$\bigstar$ To Find

The density of Methane at 27°C and 2 atm

$\bigstar$ Solution

We know that

$\red{\rm \longrightarrow d=\dfrac{PM}{RT}}$

Here

• d = density
• P = pressure
• M = mass
• R= gas constant
• T = temperature

According to the question

We are asked to find the density of methane at 27°C and 2 atm

Therefore

We must find "d"

Given that

Methane at 27°C and 2 atm

Hence

• T = 27°C = 300 K
• P = 2 atm

We know that

Mass of methane (CH₄)

[Mass of Carbon= 12 g/mol]

[Mass of Hydrogen= 1 g/mol]

Hence

M = 12 + (4 x 1) = 16 g/mol

Therefore

• M = 16 g/mol

We also know that

• R = 0.082 L atm/K mol

Substituting the values

We get

$\blue{\rm \longrightarrow d=\dfrac{2 \times 16}{0.082 \times 300} \ g/L}$

On further simplification

We get

$\orange{\rm \longrightarrow d \approx 1.299 \ g/L}$

Hence

$\pink{\rm \longrightarrow d = 1.30 \ g/L}$

Therefore

Density of Methane at 27°C and 2 atm = 1.30 g/L

Answer 2

AnsweR :-

We are given to find the The dencity of Methane at 27°C and 2 atm.

To FinD :-

• The density of Methane @ 27 ° C and 2 atm

SoluTioN :-

We Know that,

$\boxed{ \bold{ \pink{★d = \frac{PM}{RT} }{} }{} }{}$

Where,

d = density

p = pressure

M = Mass

R = Gas constant

T = Temperature

According to the Question!

We should find the 'd ' of Methane at 27 ° C and 2 atm

It is Given That,

• T = 27 °C = 300k

• Pressure = 2 atm

Mass of Methane ( CH4 )

By Finding out value of masses of each elements then adding.

Mass of Carbon = 12 - 1 Carbon Molecule.

Mass of Hydrogen = 1 - 4 Hydrogen molecules

Hence Mass of CH4 = (12*1) + (1*4) = 16g/mol

We also know that,

• R = 0.082L atm / K mol

Substitute The values we get,

$\bold{ \purple{★d = \frac{2 \times 16}{0.082 \times 300} g/L}{} }{}$

On Further Simplification we get,

$\boxed{ \bold{ \red{★d = 1.299g/L= 1.30g/L}{} }{} }{}$

Hence the density of Methane at 27°C and 2 atm = 1.30 g/L