Question

the density of premium metal is 7.2g cm/3. If the unit cell is cubic edge length of the 289 cubic metre. Determine the type of unit cell.​

Answer 1

Answer:

879.89 cm/ 567m =567m/879.89cm

Answer 2

Answer:

BCC

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Explanation:

The expression for density is as follows:

Density =d=

a

3

×N

A

n×M

GIven: d=7.2 g cm

−3

a=289 pm =289×10

−10

cm

Molecular weight of Cr =52 g mol

−1

n=

M

d×a

3

×N

A

=

52

7.2×(289×10

−10

)

3

×6.023×10

23

n=

52

7.2×2.41×10

−23

×6.023×10

23

n=

52

7.2×2.41×6.023

=2

Since there are 2 Cr atoms in a unit cell, Cr crystallizes in bcc unit cell.