Question

The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?​

Answer 1

Answer:

0.052 cm³

Explanation:

Volume = Mass / Density

= 1.00 g / (19.3 g/cm³)

≈ 0.052 cm³

Answer 2

Given :-

• Density of pure gold = 19.3g/cm³
• Mass of pure gold = 1g

To find :-

• Volume of pure gold

Solution :-

➭ Density = Mass/volume

➭ Volume = Mass/density

➭ Volume = 1/19.3

➭ Volume = 10/193

➭ Volume = 0.05 cm³

☞ 1m³ = 1000000

Hence,

• Volume of cube is 5 × 10^(-8)