Question

The density of sea water is 1025 ᵏᵍ/ᵐ³, the maximum depth of the Atlantic ocean is 8500 m. (1 kPa = 1000 Pa and g = 10 ᵐ/ˢ²) What will be the water pressure at this depth?

Answer 1

Answer:

Pressure = 1.01 × 10^3 + (1025 × 8500 × 10)

= 1.01 × 10^3 + (87125000)

= 1010 + 87125000

= 87126010 pa

= 87126.01 kpa