Question

The density of silver is 10.5 g/cc. silver crystallizes in face centred cubic lattice. Calculate the radius of silver atom in cm. (Atomic mass of Ag = 107 amu) .​

Answer 1

Answer:

Density (D), number of atoms per unit cell (Z), atomic mass (M), Avogadro's number (N0) and edge length (a) are related as below:

Density (D), number of atoms per unit cell (Z), atomic mass (M), Avogadro's number (N0) and edge length (a) are related as below:D=N0a3ZM

Density (D), number of atoms per unit cell (Z), atomic mass (M), Avogadro's number (N0) and edge length (a) are related as below:D=N0a3ZM10.5=6.023×1023×(4.07×10−8)34M

Density (D), number of atoms per unit cell (Z), atomic mass (M), Avogadro's number (N0) and edge length (a) are related as below:D=N0a3ZM10.5=6.023×1023×(4.07×10−8)34MM=107.9 g/mol

Density (D), number of atoms per unit cell (Z), atomic mass (M), Avogadro's number (N0) and edge length (a) are related as below:D=N0a3ZM10.5=6.023×1023×(4.07×10−8)34MM=107.9 g/molHence, the atomic mass of silver is 107.9 g/mol.

please mark me as branliest