Question

The density of silver is 10.5x 103 kg/m3, the atomic weight of silver is 107.9 u. Assuming that each silver atom provides one conduction electron calculate the density of electrons. The conductivity of silver at 200C is 6.8 x 107 (ohm-m)-1. Calculate the mobility of electrons in silvesilv​

Answer 1

The density of silver is 10.5x 103 kg/m3, the atomic weight of silver is 107.9 u. Assuming that each silver atom provides one conduction electron calculate the density of electrons. The conductivity of silver at 200C is 6.8 x 107 (ohm-m)-1. Calculate the mobility of electrons in silvesilv

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Answer 2

given mass density and atomic weight of silver, find the electron density and mobility for given conductivity

Explanation:

1. given mass density of silver denoted by 'D' , $D=10.5x10^3kg/m^3$                                      given atomic weight of silver denoted by 'A', $A=107.9$μ

                                                                                       $= 107.9x1.6x10^{-27$

                                                                                       ≈$1.8x10^{-25}kg$    

    2. since each atom provides one conduction electron, density of

        electrons denoted as $D_e$ is given by,

                                $D_e=\frac{D}{A}$

                                $D_e$ $= \frac{10.5x10^3}{1.8x10^{-25}}= 5.83x10^{28} e^-/m^3$    

     3. now we know that mobility of electrons denoted by μ$_e$ for a given

         conductivity σ is given by , μ$_e=$σ$/eD_e$                                                              

                                                       μ$_e=\frac{6.8x10^7}{5.83x10^{28}x1.6x10^{-19}}$

                                                       μ$_e=7.2x10^{-3} m^2/Vs$