the density of the liquid varies as ρ = ρ∘y^3 the pressure at the depht of h is
Answers
Answer:
po+(rho)gh³/3
Explanation:
dp/dy=(rho)g
Answer:
The density of the liquid varies as ρ = ρ∘y^3 the pressure at the depht of h is P=ρgh
Explanation:
Step : 1 Thus, the pressure caused by the weight of any fluid with an average density at whatever depth below its surface is represented by the equation P=hg P = h g. This equation holds to considerable depths for liquids, which are almost incompressible. At various depths, a liquid has a variable pressure. As depth deepens, pressure rises. The weight of the water column above contributes to the pressure in a liquid. This pressure works in all directions because a liquid's particles are closely packed.
Step : 2 The relationship between pressure and depth is inversely proportional. This is a result of the larger water column pressing down on an object that is submerged. In contrast, pressure drops as items are raised and the depth is lowered. Calculating pressure involves dividing the force by the area. P = F A, or pressure equals force area Text pressure is equal to frac text pressure, area text pressure, force text, and area text, or P = frac F A. A compound measurement created from force and area is pressure. The force per unit area is equal to the pressure.
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