The density of the liquid varies as ρ = ρ∘y^3 the pressure at the depht of h is
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ρ=2ρo(a+βh)
V=ρom
Downward force, F=mg−ρom2ρo(a+βh)g
F=mg((1−2a)−2βh)
So F is proportional to displacement from center position which is mg(1−2a) below surface
Therefore, the motion is SHM.
A = mg(1−2a)
k=2mgβ
Also, k=mω2
=> ω=2gβ
vmax=ωA=2β(2−a)g
Answer A
hope it helps uu
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